ÈËÉú¾ÍÊDz©¼¤¹âÀäË®»ú¿ÉÓÃÓÚ
×ÏÍ⼤¹âÆ÷µÄÀäÈ´ £¬ÈËÉú¾ÍÊDz©Ò²Ò»Ö±¹Ø×¢×ÏÍ⼤¹âµÄÐÂÊÖÒÕºÍÉú³¤Ô¶¾°¡£½ñÌìÎÒÃÇÀ´ÏàʶһÏîÐÂÊÖÒÕ£¬Èð·áºã½âËøµÄ³¬ºñ²£Á§ÍêÉÆ´ò¿×£¬½öÐè0.1Ãë¡£
²£Á§ÊÇÎÒÃÇÉúÑÄÖг£¼ûµÄ¹¤ÒµÖÊÁÏ,Åãͬ×Ų£Á§¹¤ÒÕÆ·µÄÐèÇóÈÕÒæÐËÍú,²£Á§Ó¦Óõij¡¾°Ò»Ö±À©´ó,¶àÑù»¯µÄÐèÇó´ßÉúÁ˲£Á§´ò¿×ÊÖÒյı¬·¢ÓëÉú³¤¡£ÖÚËùÖÜÖª,²£Á§Ò×Ëé,ÈÝÒ×Êܵ½ÍâÁ¦µÄÓ°Ïì,ÒÔÊǶԲ£Á§´ò¿×ÊÖÒÕÓÐןÜÊǸߵÄÒªÇó¡£
¹Å°åµÄ»úе´ò¿×·½·¨»á¶Ô²£Á§Ôì³ÉËðÉË,ÑÏÖØ½µµÍÁ¼Æ·ÂÊÓëÑŹ۶È,ÈÝÒ×Òòµ¼Ö²£Á§·ºÆðËéÁÑ¡¢´ò³öÀ´µÄ¿×¾Þϸ·×Æç´Ó¶øÏûºÄ¹ý¶àµÄÖÊÁÏÒÔ¼°ÆÌÕÅÁËÈ˹¤Ê±¼ä,½µµÍÁËÉú²úЧÂÊ¡£
¶øÈð·áºã×ÏÍ⼤¹âÆ÷S9,Ôò½«¹â°ßµÄÖ±¾¶ËõСµ½Î¢Ã×¼¶,ÒÔ´Ë»ñµÃ¸ßÃܶȵ魯â,ÏÕЩ¿ÉÒÔÔÚÈκÎÖÊÁÏÉϾÙÐдò¿×,ÈçÌÕ´É¡¢²£Á§µÈ,²¢ÇÒ¿×¾¶Ð¡,´ò¿×ËÙÂÊ¿ì,ЧÂʸß,ÒÀ¸½ÏȽøµÄÊÖÒÕ,²»µ«¿ÉÒÔʵÏÖ¸ßЧµÄ²£Á§ÇиîºÍ×ê¿×,»¹¿ÉÒÔÓÐÓÃïÔÌÇиî±À±ßµÄ¹æÄ£ºÍÄÚÁÑÎÆ,°ü¹Ü²£Á§µÄÇ¿¶È¡£
¼¤¹â´ò¿×ÊôÓÚÎÞ½Ó´¥¼Ó¹¤·½·¨,ÊÇʹÓø߹¦ÂÊÃܶȼ¤¹âÊøÕÕÉä±»¼Ó¹¤ÖÊÁÏ,²»ÊÜÖÊÁϵÄÓ²¶È¡¢¸ÕÐÔ¡¢Ç¿¶ÈºÍ´àÐԵȻúеÐÔÄܵĿØÖÆ¡£
S9ϵÁм¤¹âÆ÷¹âÊøÖÊÁ¿ºÃ,¾Û½¹¹â°ß¸üС,ʹÖÊÁϺܿ챻¼ÓÈÈÖÁÆû»¯Î¶È,Õô·¢Ðγɿ׶´,¾ßÓиßЧÂÊ¡¢Çå¾²¡¢Îȹ̡¢²Ù×÷ÇáÓ¯µÈÌØµã¡£
¿É´ò¿×¹æÄ£:С¿×:1.00¡«3.00(mm);´ÎС¿×:0.40¡«1.00(mm);³¬Ð¡¿×:0.1¡«0.40(mm);΢¿×:0.01¡«0.10(mm);´Î΢¿×:0.001¡«0.01(mm);³¬Î¢¿×:<0.001(mm),¶Ô²£Á§ÈÝÆ÷´ò΢¿×¿ÉÒÔÇáËɽâ¾ö¡£
ͬʱ,¼¤¹â²úÆ·¿É¶Ô²£Á§¾ÙÐи߾«¶È´ò¿×,¿É²Ù×÷ÐÔÇ¿,²»»á¶Ô²ÄÖÊÔì³ÉÆÆËð¡£²Ù×÷¼òÆÓ,»¹ÓµÓÐÆæÒìµÄµ÷QÊÖÒÕºÍÈ«Êý×ÖÖÇÄܵçÔ´¿ØÖÆÊÖÒÕ,ÉÏÊÖ±¾Ç®µÍ¡£ÓëͬÀàÐͲúÆ·Ïà±È,³ö¹â¸üÎȹÌ,ÓÅÔ½µÄ¹âÊøÖÊÁ¿(M2<1.2),ÔÚËùÓÐÆµÂʹæÄ£ÄÚ¶¼¿ÉÒÔÑÏ¿á°ü¹Ü;ÆäÂö³å¿í¶È<20ns@30k,¼Ó¹¤Ê±ÈÈÓ°ÏìÇøÓò¼«Ð¡¡£
¿É´ò¿×¹æÄ£:С¿×:1.00¡«3.00(mm);´ÎС¿×:0.40¡«1.00(mm);³¬Ð¡¿×:0.1¡«0.40(mm);΢¿×:0.01¡«0.10(mm);´Î΢¿×:0.001¡«0.01(mm);³¬Î¢¿×:<0.001(mm),¶Ô²£Á§ÈÝÆ÷´ò΢¿×¿ÉÒÔÇáËɽâ¾ö¡£
ȪԴ£ºÈð·áºã